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Summer/Winter Coding(~2018) 예산 (test case 전부 통과)

d	budget	result
[1,3,2,5,4]	9	3
[2,2,3,3]	10	4

 

def solution(d, budget):
    d.sort()  # [1, 2, 3, 4, 5]
    answer = 0
    if sum(d) <= budget:
        answer += len(d)
    if sum(d) > budget :
        arr = []
        for i in d :
            if sum(arr) <= budget :
                arr.append(i)
            if sum(arr) > budget :
                pass
        answer += len(arr) -1
    return answer

ㅇ

def solution(n):
    answer = 0
    n = int(n)
    if n**(1/2) == int(n**(1/2)) :
        answer = (n**(1/2)+1)**2
    else :
        answer = -1
    return answer

 

def solution(s):
    
    num ={}
    num['one'] = 1
    num['two'] = 2
    num['three'] = 3
    num['four'] =4
    num['five'] = 5
    num['six'] = 6
    num['seven'] = 7
    num['eight'] = 8
    num['nine'] = 9
    num['ten'] = 10
    
    n_list = ['one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight','nine', 'ten']
    ans_list =[]
    for i in range(len(s)) :
        if s[:i+1].isdigit() == True : 
            ans_list.append(s[:i+1])
            s = s[i+1:]
        if s[:i+1] in n_list :
            target = s[:i+1]
            change = num[target]
            ans_list.append(change)
            s = s[i+1:]
    print(ans_list)
    #answer = int("".join(ans_list))
    #return answer

input , output

s	result
"one4seveneight"	1478
"23four5six7"	234567
"2three45sixseven"	234567
"123"	123

 

완주하지 못한선수 -> 런타임 에러

def solution(participant, completion):
    for i in range(len(completion)) :
        if completion[i] in participant :
            participant.remove(completion[i])
            answer = "".join(participant)
    return answer

 

모의고사 -> 런타임 에러

def solution(answers):
    ans1 = [1, 2, 3, 4, 5]
    ans2 = [2, 1, 2, 3, 2, 4, 2, 5] 
    ans3 = [3, 3, 1, 1, 2, 2, 4, 4, 5, 5]
    score_1 = 0
    score_2 = 0
    score_3 = 0
    dict_score = {}
    for i in range(len(answers)) :
        if answers[i] == ans1[i] :
            score_1 += 1
            dict_score[1] = score_1
        if answers[i] == ans2[i] :
            score_2 += 1
            dict_score[2] = score_2
        if answers[i] == ans3[i] :
            score_3 += 1
            dict_score[3] = score_3
        answer = list(dict_score.keys())
        answer.sort()
    return answer

 

k번째 수 -> 런타임 에러

def solution(array, commands):
    ans = list()
    for i in [0, 1, 2]:
        fst = commands[i][0]
        sec = commands[i][1]
        thr = commands[i][2]

        new = array[fst-1 : sec]
        new.sort()
        answer = new[thr-1]
        ans.append(answer)
    return ans